A snail is at the bottom of a 10 foot well. Every day, he crawls up 3 feet, but at night, he slips
down 2 feet. How many days will it take for him to get
out of the well?

10 days.

Step-by-step explanation:

3-2 = 1 foot of progress per day.

8 days

Step-by-step explanation:

We get 8 days because the snail gets one foot higher every day. By the morning of the 8th day, the snail is 7 feet up and just needs to climb its daily 3 feet and it will be out of the well. You don't need 10 days because the snail only falls at night.

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50