When Joseph moved into a new house, he planted two trees in his backyard. At the time of planting, Tree A was 16 inches tall and Tree B was 37 inches tall. Each year
thereafter, Tree A grew by 6 inches per year and Tree B grew by 3 inches per year. Let
A represent the height of Tree At years after being planted and let B represent the
height of Tree B t years after being planted. Write an equation for each situation, in
terms of t, and determine the interval of time, t, when Tree A is taller than Tree B.
A = 6t + 16
B
3t + 37
w
Tree A is taller than Tree B when t
inches per year y

true

step-by-step explanation:

the y will be in still but your answer will be y x 3

step-by-step explanation:

jk: )

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240