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8.

Since they have twice as many games won as lost there are 3 parts.

The losing part and the two winning parts.

The winning part is the games while the losing part is the games.

Just multiply by the games played to find the games won.

The ravens won 64 games.

10.

Make a system of equations.

Let s be the number of skips interviews and w be the number of woodys interviews.

s=w-8

s+w=20

Then just use algebra to rearrange and find each persons interviews.

For this one we can rearrange the second equation to get s=20-w.

Since we have two solutions for s we can set them equal.

w-8=20-w

2w-8=20

2w=28

w=14

Now that we have the number of woodys interviews substitute it into the first equation to get skips interviews.

s=w-8

s=14-8

s=6

So skip had 6 interviews and woody had 14 interviews.

12.

Make a system of equations

y-x=7

x+y=33

Then just use algebra to rearrange and find each amount of items.

Start by solving with substitution. (Elimination could work too im just going to use substitution.)

y-x=7

y=7+x

Substitute into the second equation

x+(7+x)=33

2x+7=33

2x=26

x=13

Now plug this x value back into the first equation

y-13=7

y=20

The number of items on one list is 13 and the number of items on the second list is 20.

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