The ordinate of a point is twice its abscissa . If its distance from the point (4,3) is √10 units ,then the coordinates of the point are ?

(1 , 2) and  (3 , 6)

Step-by-step explanation:

the point P : (x , y) -> (x , 2x)    ... ordinate of P point is twice its abscissa, y = 2x

√10 = √(x-4)² + (2x-3)²

5x² - 20x + 25 = 10

x² - 4x + 3 = 0

(x-1)(x-3) = 0

x = 1    or    x = 3

y = 2    or   y = 6

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10