Suppose (4,2) is a point on the graph y=f(x). What is a point that would be on the graph if y=10f(x)+5

Step-by-step explanation:

3,4 i think

(4 , 25)

Step-by-step explanation:

y = 10*f(x) + 5   a = 10

a*f(x): vertical stretch with factor a, if | a | > 1 then (x , y) -> (x , ay)

(4 , 2) ==> (4 , 20)

f'(x) + b : vertical translation UP b units  y = 10*f(x) + 5 , (x,y) -> (x, y+5)

(4 , 20) ==> (4 , 25)

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

bull

step-by-step explanation: