Suppose a life insurance company sells a $230,000 one-year term life insurance policy to a 24-year-old female for $200. The probability that the female survives the year is 0.999569. Compute and interpret the expected value of this policy to the insurance company. The expected value is $ (Round to two decimal places as needed

Suppose a life insurance company sells a $230,000 one-year term life insurance policy to a 24-year-old female for $200. The probability that the female survives the year is 0.999569. Compute and interpret the expected value of this policy to the insurance company. The expected value is $ (Round to two decimal places as needed

Suppose a life insurance company sells a $150,000 one-year term life insurance policy to a 23-year-old female for $260 the expected value of this policy to the insurance company will be:$198.35

Expected value=(260×0.999589)-(150,000-$260)×(1-0.999589)

Expected value=259.89314-149,740×0.000411

Expected value=$198.35

Interpretation of the Expected value:

Based on the above calculation the insurance company is expect to make an average profit of $198.35 on every 23-year-old female it insured for 1 year.

Inconclusion Suppose a life insurance company sells a $150,000 one-year term life insurance policy to a 23-year-old female for $260 the expected value of this policy to the insurance company will be:$198.35

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are