Find the midpoimt of the line segment between the points (4,-7) and (12, -1) a. (8, -4)
b. (4, -3)
c. (16, -4)
d. (4, -4)

The midpoint is the middle of the line. Thus for a line segment, it is finding the halfway point between the x and y values.

Midpoint = ( [¹/₂ (x₁ + x₂)] , [¹/₂(y₁ + y₂)])

∴ for a line segments with endpoints (4,-7) and (12, -1),

 Midpoint = ( [¹/₂ (12 + 4)] , [¹/₂(-7 - 1)])

                = ( [¹/₂ (16)] , [¹/₂(-8)])

                = (8, -4)  (OPTION A)

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

step-by-step explanation: