1/x+2 - 1/x-2 = 1

Answer fast please.

Given equation is 1/(x+2) - 1/(x-2) = 1

=> [(x-2)-(x+2)]/(x+2)(x-2) = 1

=> (x-2-x-2)/(x²-4) = 1

=> (-2-2)/(x²-4) = 1

=> -4/(x²-4) = 1

=> x²-4 = -4

=> x²-4+4 = 0

=> x² +0 = 0

=> x² = 0

The standard form is x² = 0 or x²+0x+0 = 0

Here I have used this formulae in your all questions.

The standard quadratic equation is ax²+bx+c = 0

Hope this helps!!