Recall that the height of an object t seconds after it begins moving when gravity is the only force acting on the object is given by h(t)=−16t2+v0t+h0,
where h(t) is given in feet, v0 is the initial velocity of the object in ft/sec, and h0 is the initial height of the object in feet.

If a ball is thrown directly upward from the top of a building with an initial velocity of 64 feet per second, and an initial height of 70 feet. What is the maximum height attained by the ball?
Your answer is
feet.

add an image !

step-by-step explanation:

answer: asdfghjkl,mnbv

step-by-step explanation:

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)