Using pemdas, please help with the following questions:

Step-by-step explanation:

(9 + 33 - 6) ÷ 6 - 3²

             36 ÷ 6 - 3²   p

             36 ÷ 6 - 9    e

                     6 - 9    md

                         - 3   as

(10 + 43 - 5) ÷ 6 + 5²

              48 ÷ 6 + 5²    p

              48 ÷ 6 + 25   e

                       8 + 25  md

                             33  as

(6 + 3)² + (9 - 10 + 5)

       9² + 4     p

      81 + 4      e

      81 + 4      md not used

            85     as

4 x (12 x 6 - 4²) + 9        must use pemdas inside the parentheses first

4 x (12 x 6 - 16) + 9     e   (p not used inside)

     4 x (72 - 16) + 9    md

             4 x 56 + 9    as   parentheses complete, start over

                 224 + 9    md  (pe not used)

                       233    as

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.