(7 pts) A school has 400 feet of fencing to build a set of 3 athletic fields as shown below. What dimensions should they use to build the largest possible athletic complex? Include appropriate units with your answer.
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Step-by-step explanation:

the side lengths are (400 - 4x)/2 = 200 - 2x

A = x(200 - 2x)

A = 200x - 2x²

Maximum area will occur when the derivative is set to zero.

dA/dx = 200 - 4x

0 = 200 - 4x

x = 200/4 = 50 ft

each field will be 50 x 33⅓ ft.

total area will be 5000 ft²

Which is not very big for a sports complex. I've owned houses with more floor space than that.

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values

13

step-by-step explanation:

divide the cost of the total of sodas you bought by the cost of one soda, for example:

$24.57 divided by $1.89 is 13 which means you bought 13 sodas