calculate the time taken for a train to travel 1000m if its initial is 3 m/s and it is moving at a constant acceleration of 0.1m/s^2

Step-by-step explanation:

For obects already in motion, the distance travelled, s, is:

s = vi*t + (1/2)at^2

where vi is the initial velocity, a is the acceleration, and t is the time in seconds.

We want the time, t, to reach 1000 meters.

1000 m = (3 m/s)*t + (1/2)*(0.1m/s^2)*(t^2)

(1/2)*(0.1m/s^2)*(t^2) = 0.05t^2

0.05t^2 + 3t -1000 = 0

Solve quadratic equation:

t = 114.6 seconds

easy math just plug in a and b

step-by-step explanation:

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3