This problem shows why the dual variable for an equality constraint should be urs. a Use the rules given in the text to find the dual of
max z = xy + 2x2
s. t. 3x1 + x2 ≤ 6
2x1 + x2 = 5
X1, X2 ≥ 0
b. Now transform the LP in part (a) to the normal form.
Use y and y as the dual variables for the two pri- mal constraints derived from 2x1 + x2 = 5.
c. Make the substitution y2 = y - y2 in the part (b) answer. Now show that the two duals obtained in parts (a) and (b) are equivalent.