The table shows the predicted and actual amount of snow for a local city. Snowfall (inches)
Predicted 6.75
Actual 10.25

What is the percent error for the amount of snowfall? Round the percent to the nearest tenth if necessary.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

i think 5 miles per hour

step-by-step explanation:

no

step-by-step explanation: