An object is thrown upward at a speed of 71 feet per second by a machine from a height of 6 feet off the ground. The height h of the object after t seconds can be found using the equation h = − 16 t 2 + 71 t + 6

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

both equations and proportions are better.

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

y/x of point b= y/x of point a

step-by-step explanation:

(i got the same question, this was the correct answer.)