Solve the following differential equation by variation of parameters. Fully evaluate all integrals. y′′+9y=sec(3x). Find the most general solution to the associated homogeneous differential equation. Use c1 and c2 in your answer to denote arbitrary constants, and enter them as c1 and c2. yℎ= help (formulas) Find a particular solution to the nonhomogeneous differential equation y′′+9y=sec(3x). yp= help (formulas) Find the most general solution to the original nonhomogeneous differential equation. Use c1 and c2 in your answer to denote arbitrary constants. y=

correct answer:

i^31 = -i

70,000 + 6,000 + 800 + 30

step-by-step explanation:

your answer would be b

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.