In Exercises 15–20, find the remaining zeros of a polynomial P(x) with real coefficients and with the specified degree
and zeros.
19. Degree 6; zeros: 0, 5, 1, 3i

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Assuming that the multiplicities of the five aforementioned                         roots ( {0, 5, 1, 3i, -3i} ) are each 1, the 6th zero can be any real number.  

Step-by-step explanation:

Because P(X) has real coefficients, and 3i is a zero, we conclude that -3i is also a zero of P(X).  Assuming that the multiplicities of the five aforementioned   roots ( {0, 5, 1, 3i, -3i} ) are each 1, the 6th zero can be any real number.  

step-by-step explanation:

x= 149. 24+7=31. 180-31=149

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