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Mathematics, 27.10.2021 01:40 kayli2582

Given: \overline{AC} \perp \overline{BE}AC⊥BEand \overline{AC} \perp \overline{CG}.AC⊥CG. Prove: \angle BEA \cong \angle FDG∠BEA≅∠FDG.

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Given: \overline{AC} \perp \overline{BE}AC⊥BEand \overline{AC} \perp \overline{CG}.AC⊥CG. Prove: \an...
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