In pack of ten books, three are geometry books while the rest are book on algebra. If three books are drawn at random, what is the probability that one of them is geometry book and the others are book on algebra

21/40.

Step-by-step explanation:

There are 3 geometry and 7 algebra books.

If the geometry book is drawn first probability = 3/10

If the second is algebra P = 7/9.

If the third is algebra P = 6/8 = 3/4.

So the probability  of all three being drawn in this order = 3/10 * 7/9 * 3/4

= 63/360

= 7/40.

Now there are a total of 3 ways in the order they are drawn, That is:

GAA

AGA

AAG.

So the required probability = 3 * 7/40

= 21/40.

how am i supposed to answer

step-by-step explanation:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10