6 identical bags and 3 identical shirts cost 126. 3 such bags cost as much as 2 shirts. what is the cost of one such shirt ?

18

Step-by-step explanation:

Write the information algebraically:

6b + 3s = 126

3b = 2s

(b = bags, s = shirts)

The second line in bold means that we can replace 6b with 4s

3b = 2s (multiply both sides by 2)

∴ 6b = 4s

so, 4s + 3s + 126

Now simplify:

7s = 126

We can now find s by dividing both sides by 7:

s = 126 ÷ 7 = 18

1 shirt costs 18

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

$97520

step-by-step explanation:

add 6% to the value she got from selling the house.