If h(x) = f[g(x)], use the table of values for f, g, f ′ and g ′ to find the value of h ′(1). x f(x) g(x) f ′(x) g ′(x)
1 3 2 2 6
2 1 8 5 7
3 7 2 7 9
Numerical Answers Expected!

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h ( x ) = f [ g ( x ) ]

To find h ' ( x )  

We do → f ' [ g ( x ) ] × g ' ( x )  

This is called the chain rule

Given;

g ( 1 ) = 2  →  f ' ( 2 ) = 5

g ' ( 1 ) = 6

Apply the formula

h ' ( 1 ) = f ' [ g ( 1 ) ] × g ' ( 1 )

          = f ' ( 2 ) × 6

          = 5 × 6

h ' ( 1 ) = 30

Step-by-step explanation:

what does x eaqual

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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