What is the equation of a line that passes through the point (8, -2) and is parallel to the line whose equation is 3x + 4y = 15?

y = -3/4x + 4 or 3x + 4y = 16

Step-by-step explanation:

Step 1

Find the slope of the given line

we have

3x + 4y = 15

Isolate the variable y

Subtract 3x from both sides

3x + 4y -3x = 15-3x

Divide by 4 both sides

y = -3/4x + 15/4

the slope of the given line is

m = -3/4

Step 2

Find the equation of the line that passes through  the point  and is parallel to the given line

we know that

if two lines are parallel, then their slopes are equal

The equation of the line into point-slope form is equal to

y - y₁ = m(x-x₁)

we have

m= -3/4

(x1,y1) = (8,-2)

substitute in the equation

y + 2= -3/4(x-8)

y = -3/4x + 6 - 2

y = -3/4x + 4 or 3x + 4y = 16

therefore

the answer is

y = -3/4x + 4

or

3x + 4y = 16

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

the answer i believe is 27 units.

step-by-step explanation: