The measure of the exterior angles of a quadrilateral are 4x° , 7x°, 9x° and 10x°. Find the measure of the smallest exterior.

48°

Step-by-step explanation:

the sum of the exterior angles of any polygon is 360°

so, 4x + 7x + 9x + 10x = 360

30x = 360

x = 12

smallest exterior ∡ is 4x, so 4(12) = 48°

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: