1. Expand: (a) p(7-q) =
(b) (p+3)(p+2) =

2. Factorise:
(a) 9jk-27j =
(b) w²-wy+wz =

3. Express 2/3q - 2q+3/3q² as a single fraction in the simplest form :

4. Given 1/4 q² + r = p
(i) Express r in terms of p and q :
(ii) Calculate the value of r when p= -12 and q = 6 :

5. Diagram 10 shows six algebraic terms
(2rs, 1/pq, -7s, - st, -6y, -8a)
Write all the algebraic terms in one variable :

6. Complete the following sequence
(i) -4, -1, ( ), 5, 8, 11, 14
(ii) 23, 19, 15, ( ), 7, 3, - 1
(iii) 2/5, 2, 10, ( ), 250, 1250

7. State the variable which is the subject of the formula for each of the following formulae
(a) Formula: E = mgh
Subject of formula: ( )
(b) p = qr + 1/2 sr³
Subject of formula : ( )

I NEED ANSWERS WITH CALCULATION STEPS ASAP I NEED TO HAND IN MY PAPER LATER

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: