4. If -3x -15 = 21 and 5-3(a-7)= 24 +a , what's the product of x and a?

The value of x is -12

The value of a is -3/4

Step-by-step explanation:

-3x - 15 = 21

add 15 both side we get,

-3x - 15 + 15 = 21 + 15

-3x = 36

3x = -36

Now, divide both side by 3 we get,

3x/3 = -36

x = -12

Thus, The value of x is -12

-3(a - 7) = 24 + a

-3a + 21 = 24 + a

Now, Subtract 21 from both side we get,

-3a + 21 - 21 = 24 - 21 + a

-3a = 3 + a

Now, Subtract a from both side we get,

-3a - a = 3 + a - a

-4a = 3

4a = -3

Now, divide both side by 4 we get,

4a/4 = -3/4

a = -3/4

Thus, The value of a is -3/4

4.)

-3x - 15 = 21

-3(-12) - 15 = 21

36 - 15 = 21

21 = 21

5.)

-3(a - 7) = 24 + a

-3(-3/4 - 7) = 24 -3/4

9/4 + 21 = 24 - 3/4

9/4 + 3/4 = 24 - 21

12/4 = 3

3 = 3

Hence, L.H.S = R.H.S

-TheUnknownScientist 72

i really dont know

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2