A father is now two times as old as his son. Sixteen years ago he was 6 times as old as his son. How old are the father and son now?

40 years and 20 years

Step-by-step explanation:

Let the father's age be y and son's age x

Father is currently twice son's age i.e 2x

16 years ago, the son was (x-16) years old

the father was (y-16) or (2x-16) years old(i)

The second sentence states that the father was 6 times his sons age 16 years ago i.e 6(x-16)yrs old(ii)

Equating (i) to (II) gives 2x-16 = 6(x-16)

2x-16 = 6x-96

Collecting like terms, 96-16 = 6x-2x, 80 = 4x, x = 20

Therefore, son's age is 20years and fathers age is twice son's age = 40 years

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

step-by-step explanation: