A circle passes through the vertices of a square of side 20cm. Find the radius of the circle.

14,1 cm

Step-by-step explanation:

If a circle passes through the vertices of a square then the diagonal of a square is a circle diameter.

We use Pytagoras Theorem to find out the length (L)  of the diagonal given that:

L²  =  (20)²  +  (20)²

L²  = 2* (20)²

L  = √2 * 20

L  = 1,4142* 20

L = 28,28 cm

L diagonal in the square is a diameter of the circle then radius of a circle is:

r = L/2   ⇒   r  = 28,28 /2   ⇒   r = 14,14 cm

14.1cm

Step-by-step explanation:

If a circle passes through the vertices of a square then the diagonal of a square is a circle diameter.

We use Pytagoras Theorem to find out the length (L)  of the diagonal given that:

L²  =  (20)²  +  (20)²

L²  = 2* (20)²

L  = √2 * 20

L  = 1,4142* 20

L = 28,28 cm

L diagonal in the square is a diameter of the circle then radius of a circle is:

r = L/2   ⇒   r  = 28,28 /2   ⇒   r = 14,14 cm

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

hi there!

the answer will be d: 2