A rocket is launched from ground level with an initial velocity of 224ft/sec a) How long will it take to hit the ground?
b) When will the rocket reach a height of 528 ft?

So far, so good. Remember the rocket goes up, and then comes back down again. What you have discovered so far is that the height is 528 feet 3 seconds after launch, and then it keeps going up. At some point it starts coming back down again, and at 11 seconds after launch it passes 528 feet again.

Part b is exactly the same problem, except that you use 0 instead of 528. You will get two roots for your equation again, one will be 0 because the rocket is on the ground at time 0, and the other will be the time it hits the ground on the way back down.

Step-by-step explanation:

hope this .

r3t40

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead