What is ln(y^3/7) written in expanded form? 3 ln 7−ln y

ln 7−3 ln y

3 ln y−ln 7

ln y−ln 7+3

3lny - ln7

Step-by-step explanation:

We need to look at two properties that can determine our answer, first off is the obvious rule of subtraction between two logs, when subtracted, the numbers on the right of the log must be divided together.

The other one is the y^3, which means that we need to look for a logarithm that has 3 in the front of it because when a number in front of a logarithm exists, it must turn into an exponent of the number of the right of the logarithm.

With this, we can cross out the ones without the 3 in front, which would be D. lny - ln7 + 3

Now, we see that y is the one with the exponent, meaning that the equation with the 3 in front of the logarithm of y is correct, cross out the ones without, which is A. 3ln7 - ln7

Now when subtracting, the first logarithm will be the numerator while the second logarithm will be the denominator. Leaving us with our final answer being C. 3lny - ln7

(y^3 [3lny] / 7 [ln7])

x=12 units bd= 10 units

step-by-step explanation:

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y