A chemist want to mix a 40% acid solution with a 70% acid solution to make 6 liters of a 50% acid solution. How much of each type of solution should the chemist use? Show your work. need help asap PLZZ. pls help don't fake answer to get points I need help

braniest please

Step-by-step explanation:

A chemist plans to mix 10 liters of a 40% acid solution with some 70% to obtain a 50% solution

40% = 0.4

70% = 0.7

50% = 0.5

A chemist plans to mix 10 liters of a 40%. So 10 times of 0.4 = 4

Let x be the some amount  of solution of 70%

70% of x = 0.7x

chemist obtain a 50% of solution

Amount of mixture is 10 + x

So 10+x of 50% = (10+x)*0.5

Now we frame an equation

10 * 0.4  + x * 0.7 = (10+x) * 0.5

4 + 0.7x = 5 + 0.5x

Subtract 4 and 0.5x on both sides

0.2 x= 1

Divide by 0.2

So x= 5

5 liters of 70% of solution is used.

19.

step-by-step explanation:

you add the 9 in the tens column since it is a single digit and 9 plus zero is 9 so it is 19

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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