Give the domain and range of the relation. {(-3,6), (-21,), (0,-3), (2,1), (4,13)}

Domain: {-3, -2, 0, 2, 4}

Range: {-3, 0, 1, 6, 13}

Step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse