What is the solution set of the equation x ^ 2 - 3x - 10 = 0 ? pls show work

Factors :- (x - 5) (x + 2)

Values :- x = 5, x = -2

Step-by-step explanation:

= > x^2 - 3x - 10 = 0

= > x^2 - (5 - 2)x - 10 = 0

= > x^2 - 5x + 2x - 10 = 0

= > x (x - 5) + 2 (x - 5) = 0

= > (x + 2) ( x - 5) = 0...factors

= > x = 5, - 2...values

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d

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