What is the general form of the equation of a circle with center at (a, b) and radius of length m? A.
x2 + y2 − 2ax − 2by + (a2 + b2 − m2) = 0

B.
x2 + y2 + 2ax + 2by + (a2 + b2 − m2) = 0

C.
x2 + y2 − 2ax − 2by + (a + b − m2) = 0

D.
x2 + y2 + 2ax + 2by + a2 + b2 = -m2

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²

what are the answer choices given for this problem?