In the given figure find the area of the parallelogram ABCD.

Given info:- In a Parallelogram ABCD , BC = 48 cm ,

AB = 25 cm and AE = 7 cm. And here we have to find the area of the given Parallelogram ABCD?

Explanation:-

In a Parallelogram ABCD ,

BC = 48 cmAB = 25 cmAE = 7 cm

And

∆ AEB is a right angled triangle

Right angle at E

AB is the hypotenuse

We know that

By, Pythagoras theorem

Hypotenuse² = Side² + Side²

⇛ AB² = AE²+ BE²

⇛ 25² = 7² + BE²

⇛ 625 = 49 + BE²

⇛ BE² = 625-49

⇛ BE² = 576

⇛ BE = ±√576

⇛ BE = ±24

Since the length of the side cannot be negative

⇛ BE = 24 cm

⇛ BC = AD

⇛ AD = 48 cm

⇛ AE + ED = 48 cm

⇛ 7+ED = 48 cm

⇛ ED = 48-7

⇛ ED = 41 cm

We know that

Area of a Parallelogram = bh sq.units

Area of the given Parallelogram ABCD

⇛ AD × BE or BC × AE

⇛ 48 × 24 sq.cm

⇛ 1152 sq.cm

Therefore, the area of the given Parallelogram ABCD is 1152 sq.cm

Additional comment:

Each side of the parallelogram is called its base.

Opposite sides are equal and parallel in a Parallelogram.

If you have any doubt, then you can ask me in the comments.

Ithink the answer is last one.

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote