Can someone help me with this problem please :(

2/7

Step-by-step explanation:

6 large fish and 8 small fish (half of the them are red = 4)

total fish 6 + 8 = 14 fishes

probability that one fish is one small and red fish is

there are 4 small and red fish

= 4c1 / 14c1

= (4! / (1! (4 - 1)! )  /  (14! / (1! (14-1)! )

= 4/14

= 2/7

i think the answer is b

b because it contains 40% of the possible results from the random list.  

0,1,2,3 v 4,5,6,7,8,9  

4 integers to 6 integers  

40% success vs 60% fail

step-by-step explanation: