Solving systems of equations
how would I solve this problem?
AND TYSM for y’alls help

x = -3,   y = -4

(-3, -4)

Step-by-step explanation:

solve each equation for y (the first equation is already solved for y, so just do the second equation)

-x -y =7

+x      +x

-y = x + 7      eliminate the negative by switching all signs

y = -x - 7

now that both equations equal y, you can set them equal to each other:

-x - 7 = 3x + 5

solve for x

-x - 7 = 3x + 5        move the variable to one side of the equation

+x        +x      

-7 = 4x + 5            move the constant to the other side of the equation

-5          -5

-12 = 4x                 single out x by dividing the whole thing by 4

÷4     ÷4

-3 = x

now substitute -3 for x in one of the original equations (it doesn't matter which equation)

y = 3(-3) +5      solve

y = -9 +5

y = -4

have a wonderful day! :)

the correct answer is x/3+10≥32

hope this !