Write an equation in slope-intercept form for the line passing through the two points (0,-2) and (3,0)

y = (2/3)x - 2

Step-by-step explanation:

This problem is interesting in that both the x- and the y-intercepts are given.  The y-intercept is (0, -2), and so 'b' in 'y = mx + b' must be -2:

y = mx - 2.  The x-intercept is (3, 0), so we know that y = 0 when x = 3:

0 = m(3) - 2

This latter result must be solved for m:  3m = 2, or m = 2/3.

Then the desired equation is y = (2/3)x - 2.

i dont know and i dont care for math bc it is a stupied subject

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.