The janitor at a school discovered a leak in a pipe. The janitor found that it was leaking at a rate of 7 fl oz per minute. How fast was the pipe leaking in gallons per hour? P

3.28 gallons per hour

Step-by-step explanation:

Given that the pipe is leaking at a rate of 7 fluid ounce per minute, and that we need to determine the equivalent leaking rate in gallons per hour.  It is important to establish the necessary conversion rates of fluid ounces (fl oz) to gallons (gal), and minutes to an hour.

Now that we have established the conversion rates, we can set up the following mathematical operations that will allow us to convert the leaking rate from fluid ounces per minute, to gallons per hour. We can express the conversion process in fraction form:

× ×

Start by multiplying the first two fractions together:

× = 0.546875 gallons per minute, or 0.546875 gal/min

Next, multiply 0.546875 gal/min by 60 min/hr.  This cancels out the "minute" as a unit of measurement, leaving you with gal/hr.

×  = 3.28125 gallons per hour, or 3.28 gal/hr.

Therefore, the pipe is leaking at a rate of 3.28 gallons per hour.

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation:

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh