Find there consecutive even integers such that the sum of smallest number and twice the middle number is 20 more then the largest number

The numbers are 10, 12, and 14

Step-by-step explanation:

x + 2(x+2) = x+4 + 20

x = 10

So the numbers are 10,12,14

Here is your answer

let the numbers be x,x+2,x+4

so,the equation is

x+2(x+2)=x+4+20

3x+4=x+24

2x=20

x=10

therefore the nos. are 10,12,14

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are