Which of the following can you conclude about a particle labeled 1 0n ?Check all that apply.

B and C

Step-by-step explanation:

Firstly it is not A because an alpha particle has a mass and atomic number of 2. So it would be written 2, 2, alpha.

Next, we can see by its mass number of 1 that it has one nucleon (Confirming C) as electrons have negligible mass. Because it has then has an atomic number of 0, we can conclude that it is a neutron, as a proton would have given it an atomic number of 1. This proves B to be correct and D to be incorrect.

E is incorrect as beta particles have negligible mass.

F could be correct but there is no way to tell whether or not it has an electron so we cannot tick it.

Finally G is incorrect because we already worked out the one nucleon has to be a neutron.

Hope this helped!

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.