The length of a rectangle is 6 yd longer than its width. If the perimeter of the rectangle is 68 yd, find its length and width.

Length = 20, width = 14

Step-by-step explanation:

Let  L  represent length.

Let W  represent width.

Since the length is 6 yd longer than its width:  L  =  6 + W

The formula for perimeter:  P  =  2L + 2W    

Since the perimeter is 68 yds:     68 =  2L + 2W

Substituting:                             68  =  2(6 + W) + 2W

                                               68  =  12 + 2W + 2W

                                              68  =  12 + 4W  

                                               32  =  4W

                                                W  =  8 yds

Since  L  =  6 + W  --->  L  =  14 yds

Length = 20, width = 14

Step-by-step explanation:

Let width be w, and length be w + 6.

Perimeter of a rectangle = 2l + 2w

                                  68  = 2(w + 6) + 2w

                                  68  = 2w + 12 + 2w

                                  68  = 4w + 12    [subtract 12 from both side]

                                  56  = 4w            [Divide 4 from both side]

                                   w   = 14

Plug w in l, where l = w + 6 = 14 + 6 = 20

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step-by-step explanation:

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )