Consider the LTS: M ≡ h{s0, s1, s2, s3}, {s0}, {(s0, s1),(s0, s3),(s1, s1),(s1, s2),(s2, s0),(s2, s3),(s3, s0)}, Li
where L assigns {p1, p2} to s0, {p3} to s1, {p1, p4} to s2, and {p2, p3} to s3. For each of the following
CTL wffs φ, determine whether or not M φ. If the answer is yes, briefly justify your answer;
otherwise, provide a counterexample trace/path.
(a) AFp2
(b) AG(EF(p1 ∨ p3))
(c) EX(EXp3)
(d) AG(AFp2)

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

the answer is b