Show that x^2-8x+20 can be written in the form (x-a)^2+a where a is an integer

Step-by-step explanation:

Let's complete the square

x²-8x=-20

x²-8x+(-4)²=-20+(-4)²

x²+(-4)²=-20+16

(x-4)²=-4

(x-4)²+4

where a is an integer as required

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]