If the product of two positive numbers is 56. If their difference is 10 find the numbers

smaller --- x

larger x+10

x(x+10) = 56

x^2 + 10x = 56

x^2 + 10x + 25 = 56 + 25

(x+5)^2 = 81

x+5 = 9

x=4

one is 4, the other is 14

Hope this helps you!

x=33 ; y=23

Step-by-step explanation:

Given that x+y=56 and x-y=10

Solve for either variable.

x=y+10

Substitute, replace, your solved variable in the other equation

(y+10)+y=56    Subtract 10 on both sides

2y=46     Divide by 2

y=23        Substitute answer into a given equation

x+23=56    Subtract 23 on both sides

x=33

answer: sine

step-by-step explanation:

the answer is c just got it on ed

step-by-step explanation: