The temperature of a substance in an experiment changes by −8.7°F from 10 a. m. to 1 p. m. At 5 p. m., the temperature is 33.5°F. It is 23 of what the temperature was at 1 p. m. What was the temperature at 10 a. m. of the substance?

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answer: kljdcdhjbdlchjad oac apoich a

step-by-step explanation:

add 5 subtract 1

step-by-step explanation:

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

what is

step-by-step explanation: