A pyrotechnician plans for two fireworks to explode together at the same height in the air. They travel at speeds shown below. Firework B is launched 0.25 s before Firework A. How many seconds after Firework B launches will both fireworks explode?

  3.25 seconds after B launches

Step-by-step explanation:

In the 0.25 seconds before A launches, B will have traveled ...

  distance = speed · time

  distance = (240 ft/s)(0.25 s) = 60 ft

The speed of A is 20 ft/s faster, so will close that 60 ft gap at the rate of 20 ft/s. It will take ...

  time = distance/speed

  time = 60 ft/(20 ft/s) = 3 s

The fireworks will be at the same height 3 seconds after A is launched. That is 3.25 seconds after B is launched.

Additional comment

Their heights will be (3 s)(260 ft/s) = 780 ft = (3.25 s)(240 ft/s).

5.6%

step-by-step explanation:

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (