3-√3 TAN Ꝋ= 0
Solve for if 0° ≤ < 360
(this is what I have so far)
The e...
Mathematics, 25.11.2021 14:00 smithsavannah295
3-√3 TAN Ꝋ= 0
Solve for if 0° ≤ < 360
(this is what I have so far)
The equation you are trying to solve is 3 - √(3) *tanθ = 0
You can add √(3) *tanθ to both sides: 3 = √(3) *tanθ
Divide both sides by √(3): 3/√(3) = tanθ
3/√(3) =√(3) so you can rewrite the equation as: √(3) = tanθ
√(3) is a POSITIVE value and tanθ is positive in Quadrant 1 and Quadrant 3, so your 2 solutions will there.
The angle in quadrant 1 that has a tangent of √(3) is 60 degrees.
To find the angle in quadrant 3, take the solution from quadrant 1 (that would be 60 degrees) and ADD 180 degrees to it.
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