√2 CSCꝊ - 2=0 Solve for if 0° ≤ < 360

(this is what I have so far)
Assuming your equation is square_root(2) * csc(x) -2 =0:

Add 2 to both sides: square_root(2)* csc(x) = 2

Divide both sides by square_root(2): csc(x) = 2/square_root(2) > csc(x) = square_root(2)

Write csc(x) as 1/sin(x): 1/sin(x) = square_root(2)

Cross-multiply: sin(x) *square_root(2) = 1

Divide by square_root(2) on both sides: sin(x) = 1/square_root(2) = square_root(2)/2

Now you have the equation: sin(x) = square_root(2)/2

Which angles on the unit circle have a sine equal to √(2)/2

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4

1.30

step-by-step explanation: