Find the 66th term of the arithmetic sequence 3, 13, 23, ...3,13,23,...

= 653

Explanation:

General formula: = ( + ((term) - 1) · (common difference)

= 3 + (66 - 1) · (10)

= 653

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

where is the figure