Question 3 What is the equation of the parabola that opens up, has a vertex V(5,0), and a y-intercept of 50?

y=2(x-5)^2

Step-by-step explanation:

Vertex form:

y=a(x-p)^2+q

(p,q) = (5,0)

y=a(x-5)^2

y-intercept has coordinates (0,50) so, substitute x=0 and y= 50 in the above equation to find "a"

50=a(0-5)^2

50=25a

a=2

equation

y=2(x-5)^2

could you provide figure.